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قديم 12-04-2016, 06:35 PM   #2
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4) Assume that the round trip from London to New York is 15 000 km and that the telesurgery signals propagate through optical fibers at 2x108 m/s. If the total latency was 150 ms, work out the proportion of the quoted latency that was taken up by the propagation delay and the proportion that was taken up by the video coding/decoding and temporary data storage.
Propagation delay of the signal during the round trip
= (15x10^3x10^3)/(2x10^8) = 15/(2x10^2) = 7.5x10^-2 = 0.075 S = 75 ms
Time delay due to video coding/decoding and temporary data storage = 150 – 75 = 75 ms
Then the proportion of either of them = (75 / 150)x100 = 50 %

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